X^2-8x+6.25=0

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Solution for X^2-8x+6.25=0 equation: 



X^2-8X+6.25=0

a = 1; b = -8; c = +6.25;
Δ = b2-4ac
Δ = -82-4·1·6.25
Δ = 39
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{39}}{2*1}=\frac{8-\sqrt{39}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{39}}{2*1}=\frac{8+\sqrt{39}}{2}
$

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